An incompressible fluid with density p is in a horizontal test rube of inner cross-sectional area. The
Question:
(a) Apply Newton's second law to the volume element to show that dp = pw2r'dr'.
(b) If the surface of the fluid is at radius r0 where the pressure is Po> show that the pressure p at a distance r > r0 is p = Po + pw2 (r2 – r0)/2.
(c) An object of volume V and density P ob has its center of mass at a distance R cmob, from the axis. Show that the net horizontal force on the object is pVw2Rem, where Rem is the distance from the axis to the center of mass of the displaced fluid.
(d) Explain why the object will move inward if pRcm> Pob, Rcmoo and outward if pRom < pooRcmoo.
(e) For small objects of uniform density, Rem = R.m.t,. What happens to a mixture of small objects of this kind with different densities in an ultracentrifuge?
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
Related Book For
Fundamentals of Thermal-Fluid Sciences
ISBN: 978-0078027680
5th edition
Authors: Yunus A. Cengel, Robert H. Turner, John M. Cimbala
Question Posted: