Lead forms compounds in the 12 and 14 oxidation states. All lead(II) halides are known (and are
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PbX4 → PbX2 + X2
Suppose 25.00 g of a lead(IV) halide reacts to form 16.12 g of a lead(II) halide and the free halogen. Identify the halogen.
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PbX 4 PbX 2 X 2 from the equation mol PbX 4 ...View the full answer
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