Let A and B be oversvables, suppose the simultaneous eigenkets of A and B {|, b>} form
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Let A and B be oversvables, suppose the simultaneous eigenkets of A and B {|α’, b’>} form a complete orthonormal set of base kets. Can we always conclude that [A, B] = 0? If your answer is yes, prove the assertion, if your answer is no, give a counterexample.
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Yes Proof uses completeness and orthonormality ...View the full answer
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Deepak Kumar
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