One way to measure ionization energies is ultraviolet photoelectron spectroscopy (UPS, or just PES), a technique based on the photoelectric effect. In PES, monochromatic light is directed onto a sample, causing electrons to be emitted. The kinetic energy of the emitted electrons is measured. The difference between the energy of the photons and the kinetic energy of the electrons corresponds to the energy needed to remove the electrons (that is, the ionization energy). Suppose that a PES experiment is performed in which mercury vapor is irradiated with ultraviolet light of wavelength 58.4 nm.
(a) What is the energy of a photon of this light in eV?
(b) Write an equation that shows the process corresponding to the first ionization energy of Hg.
(c) The kinetic energy of the emitted electrons is measured to be 10.75 eV. What is the first ionization energy of Hg in kJ/mol?
(d) Using Figure 7.9, determine which of the halogen elements has first ionization energy closest to that of mercury.

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2372 2081 1312 1681 1402 1314 Ar C 1521 B 1086 801 A 786 Ga 762 520 M S 1251 1012 | 1000 muu 10'-- As I se 1140 Br 1351 Zn 578 C Sc K 599 633 | 65 717 T63760 737 746 651 | 653 Xe 579 109 810 17170 549 600 640 1652684 710 20 804 709 Ba Lu 770 760 840 880 1037 58g 716703 812 1A 2A 3A AA 5A 6A 1A SA Increasing ionization energy