A parallel-plate capacitor is constructed by filling the space between two square plates with blocks of three dielectric materials, as in Figure P26.61. You may assume that ℓ, d. (a) Find an expression for the capacitance of the device in terms of the plate area A and d, 11, 12, and 13. (b) Calculate the capacitance using the values A = 1.00 cm2, d = 2.00 mm, 11 = 4.90, 12 = 5.60, and 13 = 2.10.

Transcribed Image Text:

Ko d/2