Repeat Exercise 2 using = 1.3. In Exercise 2 a. 4x1 + x2 x3 =

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Repeat Exercise 2 using ω = 1.3.
In Exercise 2
a. 4x1 + x2 − x3 = 5,
−x1 + 3x2 + x3 = −4,
2x1 + 2x2 + 5x3 = 1.
b. −2x1+ x2 + 1/2 x3 = 4,
x1−2x2 - 1/2 x3 = −4,
x2 + 2x3 = 0.
c. 4x1 + x2 − x3 + x4 = −2,
x1 + 4x2 − x3 − x4 = −1,
−x1 − x2 + 5x3 + x4 = 0,
x1 − x2 + x3 + 3x4 = 1.
d. 4x1 − x2 = 0,
−x1 + 4x2 − x3 = 5,
− x2 + 4x3 = 0,
+ 4x4 − x5 = 6,
− x4 + 4x5 − x6 = −2,
− x5 + 4x6 = 6.
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Numerical Analysis

ISBN: 978-0538733519

9th edition

Authors: Richard L. Burden, J. Douglas Faires

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