Set up, but do not evaluate, an integral that represents the area of the surface obtained by
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57. x t-t, y = . 58. x = sin'r, y = sin 31, 1<1<2 0<1< n/3
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2 dr 57 xtt yt 1t2 dt dt so S 22ny ds 21214t dt 8...View the full answer
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