Show that (a) (1 + i)i = exp (-/4 + 2n) exp (I ln 2/2) (n =
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(a) (1 + i)i = exp (-π/4 + 2nπ) exp (I ln 2/2) (n = 0, ±1, ±2, ...);
(b) (−1)1/π = e(2n+1)i (n = 0,±1,±2, . . .).
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In each part below n 0 1 2 a Si...View the full answer
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Related Book For
Complex Variables and Applications
ISBN: 978-0073051949
8th edition
Authors: James Brown, Ruel Churchill
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