Question: Solve the system by the method of substitution. 1. 2. Sx - y = 0 (2x + y = 0 2 Sx - 2y =

Solve the system by the method of substitution.
1.

Sx² - y = 0 (2x + y = 0 2х

2.

Sx - 2y = 0 13х — у? %3D 0 %3D ||

Sx - y = 0 (2x + y = 0 2 Sx - 2y = 0 13 ? %3D 0 %3D ||

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