let G = {e, a, b} be a cyclic group of order 3 with identity element e.
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let G = {e, a, b} be a cyclic group of order 3 with identity element e. Write the element in the group algebra Z5G in the form
re + sa + tb for r, s, t ∈ Z5.
(3e + 3a + 3b )4
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Because e a b is a cyclic multiplicative group we have aa b bb a ab ba e and of course e acts as ide...View the full answer
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