Referring to Fig. 32.13, where AQ bisects angle OAP, show that the regular 10-gon is constructible (and
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Referring to Fig. 32.13, where AQ̅ bisects angle OAP, show that the regular 10-gon is constructible (and therefore that the regular pentagon is also).
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36° 1 1 Q 32.13 Figure A P
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Because OA OP OAP AP O 180 36 2 72 Then QAP 36 so triangle OAP is similar t...View the full answer
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