Radial symmetry reduces (5) to 2 u = u rr + u r /r. Derive this
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Radial symmetry reduces (5) to ∇2u = urr + ur/r. Derive this directly from ∇2u = uxx + uyy. Show that the only solution of ∇2u = 0 depending only on r = √x2 + y2 is u = α ln r + b with arbitrary constants α and b.
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