Show that if R x /R 3 = R 1 /R 2 in the figure, then I
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Show that if Rx/R3 = R1/R2 in the figure, then I = 0. (R0 is the resistance of the instrument by which I is measured.) This bridge is a method for determining Rx. R1, R2, R3 are known. R3 is variable. To get Rx, make I= 0 by varying R3. Then calculate Rx = R3R1/R2.
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To show that I 0 when RxR3 R1R2 in the given bridge circuit we can analyze the circuit using Kirchho...View the full answer
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