(a) Show that the analogue of Theorem 7.11 is false for nilpotent groups [Consider S 3 ]....
Question:
(a) Show that the analogue of Theorem 7.11 is false for nilpotent groups [Consider S3].
(b) If H < C( G) and G/H is nilpotent, then G is nilpotent.
Theorem 7.11
(i) Every subgroup and every homomorphic image of a solvable group is solvable. (ii) if N is a normal subgroup of a group G such that N and G/N are solvable, then G is solvable.
SKETCH OF PROOF.
{i) If ∫: G →H is a homomorphism [epimorphism], verify that ∫(Gi) < H(i)[∫(Gi) = H(i)] for all i. Suppose ∫ is an epimorphism, and G is solvable. Then for some n, (e) = ∫(e) = ∫(G(n)) = Hn, whence His solvable. The proof for a subgroup is similar.
(ii) Let ∫: G →G/ N be the canonical epimorphism. Since G/ N is solvable, for some n ∫(G(n)) = (G/N)(n) = (e). Hence G(n)< Ker ∫ = N.Since G(n) is solvable by
(i), there exists k ϵ N* such that G(n+k) = (G(n))(k) = (e). Therefore, G is solvable.
Step by Step Answer:
Algebra Graduate Texts In Mathematics 73
ISBN: 9780387905181
8th Edition
Authors: Thomas W. Hungerford