A Newtonian fluid with $mathrm{SG}=0.8$ is forced through a capillary tube at a rate of $5 mathrm{~cm}^{3}
Question:
A Newtonian fluid with $\mathrm{SG}=0.8$ is forced through a capillary tube at a rate of $5 \mathrm{~cm}^{3} / \mathrm{min}$. The tube has a downward slope of $30^{\circ}$ to the horizontal, and the pressure drop is measured between two taps located $40 \mathrm{~cm}$ apart on the tube using a mercury manometer, which reads $3 \mathrm{~cm}$. When water is forced through the tube at a rate of $10 \mathrm{~cm}^{3} / \mathrm{min}$, the manometer reading is $2 \mathrm{~cm}$.
(a) What is the viscosity of the unknown Newtonian fluid?
(b) What is the Reynolds number of the flow for each fluid?
(c) If two separate pressure transducers, which read the total pressure directly in psig, were used to measure the pressure at each of the pressure taps directly instead of using the manometer, what would be the difference in the transducer readings?
Step by Step Answer:
Chemical Engineering Fluid Mechanics
ISBN: 9781498724432
3rd Edition
Authors: Ron Darby, Raj P Chhabra