Given y = ax2 + bx +

c, prove that the coordinates of the vertex of a parabola are the ordered pair

[–b/2a, (4ac — b2)/4a], as was asserted in Section 3.6.

The vertex is the maximum or minimum point of a parabola. Finding the critical point x at which the given function is optimized,

Then substituting x = —b/2a into the function to solve for y,

Transcribed Image Text:

y' = 2ax+b=0 x = b 2a