Redo Problem 9.17, given (a) y (x+5x-8)6 Let y=u, u = x + 5x - 8, then

Redo Problem 9.17, given

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(a) y (x+5x-8)6 Let y=u, u = x + 5x - 8, then dy/du = 6u5 and du/dx = 2x + 5. Substituting in (9.6), dy dx = 6u5 (2x+5)= (12x+30)u But u x+5x8. Substituting, therefore, = dy dx = (12x+30)(x2+5x-8)5 (b) y = -4(x-3x+9)5 Let y = -4u5 and u= x-3x+9. Then, dy/du == -20u4, du/dx=2x-3, and dy dx dy dx -20u (2x-3)= (-40x +60)u4 == = (-40x +60) (x -3x+9)4