A uniformly distributed load on beam (A B C) in Figure P6.9 causes it to sag. To
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A uniformly distributed load on beam \(A B C\) in Figure P6.9 causes it to sag. To counteract this sag, a cable and post are added beneath the beam. The cable is tensioned until the force in the post causes a moment equal in magnitude, but opposite in direction, to the moment in the beam. Determine the forces in the cable and the post, and determine the reactions at \(A\) and \(C\).
P6.9
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