In Exercises use the Special Integration Formulas (Theorem 8 2) to find the indefinite integral Data from in Theorem 8 2 THEOREM 8 2 Special Integration Formulas (a 0) 1 1 S 1 du 1 ( 2 3 u2 a du Sv u a du a arcsin a uv c 1 (u a n u u al) C u a 1 (u u a a u u al) C...

In Exercises use the Special Integration Formulas (Theorem 8.2) to find the indefinite integral. Data from in

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In Exercises use the Special Integration Formulas (Theorem 8.2) to find the indefinite integral.

Data from in Theorem 8.2

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In Exercises use the Special Integration Formulas (Theorem 8.2) to find the indefinite integral. Data from in Theorem 8.2 THEOREM 8.2 Special Integration Formulas (a > 0) 1. 1. S - 1 du = = 1/(= 2....
In Exercises use the Special Integration Formulas (Theorem 8.2) to find the indefinite integral. Data from in Theorem 8.2 THEOREM 8.2 Special Integration Formulas (a > 0) 1. 1. S - 1 du = = 1/(= 2....
In Exercises use the Special Integration Formulas (Theorem 8.2) to find the indefinite integral. Data from in Theorem 8.2 THEOREM 8.2 Special Integration Formulas (a > 0) 1. 1. S - 1 du = = 1/(= 2....
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In Exercises use the Special Integration Formulas (Theorem 8.2) to find the indefinite integral. Data from in

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THEOREM 8.2 Special Integration Formulas (a > 0) 1. 1. S√α² - 1² du ² = = 1/(₁²³= 2. 3. /u²2 - a² du Sv √u² + a² du a arcsin a + uv@ -ử +c = = 1/² (₁₁√u² − a² − α² [n]u + √u² − a²l) + C₁ u > a = = ²1 (u√/u² + a² + a²³\n\u + √√u² + a²l) + C

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Let u 5x a 1 du 5 dx 2 ...View the full answer

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