Let J n = dx/(x 2 + 1) n . (a) Compute J 1 . (b)
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Let Jn = ∫ dx/(x2 + 1)n.
(a) Compute J1.
(b) Use Integration by Parts to prove
(c) Use this recursion relation to calculate J2 and J3.
Transcribed Image Text:
X Jan+1 = (1 - 2 ) x + (2n) (x² + 1)² Jn 2n
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dx x2 1 b Use Integration a J Then and Now S Therefore x x2 11 Jn tan xC by Parts with ...View the full answer
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