Let r(t) = (x(t), y(t), z(t)) be a path with curvature (t) and define the scaled path
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Let r(t) = (x(t), y(t), z(t)) be a path with curvature κ(t) and define the scaled path r1(t) = (λx(t), λy(t), λz(t)), where λ ≠ 0 is a constant. Prove that curvature varies inversely with the scale factor. That is, prove that the curvature κ1(t) of r1(t) is κ1(t) = λ−1κ(t). This explains why the curvature of a circle of radius R is proportional to 1/R (in fact, it is equal to 1/R). Use Eq. (3).
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k(t) = ||r'(1) r"(t)|| ||r' (t)||
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We have Hence The resulting curvature k and the original curvature are rt1 ...View the full answer
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