Complete the following steps to find the values of p 0 for which the series converges a Use the Ratio Test to show that converges for p 2 b Use Stirlings formula, k 2k k k e k for large k, to determine whether the series converges when p 2 135 (2k 1) p k k 1 8 135 (2k 1) p k k 1...

a Use the Ratio Test 135 2k 1 pk1k1 pk k 135 2k 1 2k 1 k 1p and this expression has limitas k ...

Complete the following steps to find the values of p > 0 for which the series converges.

Question:

Complete the following steps to find the values of p > 0 for which the series 1•3•5•· · (2k – 1) p*k! k=1 8. converges.

a. Use the Ratio Test to show that 1•3•5· ·· (2k – 1) p*k! k=1 converges
for p > 2.

b. Use Stirling’s formula, k! ≈ √2k k^ke^-k for large k, to determine whether the series converges when p = 2.

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Calculus Early Transcendentals

ISBN: 978-0321947345

2nd edition

Authors: William L. Briggs, Lyle Cochran, Bernard Gillett

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Question Posted: Apr 13, 2019 09:55 AM

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Complete the following steps to find the values of p > 0 for which the series converges.

Question:

1•3•5•· · (2k – 1) p*k! k=1 8. 1•3•5· ·· (2k – 1) p*k! k=1

Step by Step Answer:

a Use the Ratio Test 135 2k 1 pk1k1 pk k 135 2k 1 2k 1 k 1p and this expression has limitas k ...View the full answer

Calculus Early Transcendentals

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1•3•5•· · (2k – 1) pk! k=1 8. 1•3•5· ·· (2k – 1) pk! k=1