Question: Let H be the hyperbola x 2 - y 2 = 1 and let S be the 2-by-2 square bisected by the asymptotes of H.

Let H be the hyperbola x2 - y2 = 1 and let S be the 2-by-2 square bisected by the asymptotes of H. Let R be the anvil-shaped region bounded by the hyperbola and the horizontal lines y = ±p (see figure).

a. For what value of p is the area of R equal to the area of S?

b. For what value of p is the area of R twice the area of S?

УА Н: 22 — у? %3D 1 y = p х 2 y = -p Anvil -- - --

: 22 ? %3D 1 y = p 2 y = -p Anvil -- - --

Step by Step Solution

3.46 Rating (159 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

a The area of the anvil is A 4 f 1 y dy 4 ftan p sec t dt 2p1 p 2ln1p p ... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Calculus Early Transcendentals Questions!