Show that d/dx (ln kx) = d/dx (ln x), where x > 0 and k is a

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Show that d/dx (ln kx) = d/dx (ln x), where x > 0 and k is a positive real number.

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Calculus Early Transcendentals

ISBN: 978-0321947345

2nd edition

Authors: William L. Briggs, Lyle Cochran, Bernard Gillett

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Question Posted: Feb 13, 2019 09:50 AM

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Show that d/dx (ln kx) = d/dx (ln x), where x > 0 and k is a

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ddx lnkx 1kxk 1x This is v...View the full answer

Calculus Early Transcendentals

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