In Exercises 17 through 20, solve the given initial value problem using either integration by parts or a formula from Table 6.1. Note that Exercises 19 and 20 involve separable differential equations.

dy/dx = x ln √x, where y = 3 when x = 1

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TABLE 6.1 A Short Table of Integrals 1. 2. 3. 4. 5. 6. 7. 8. Sä a + bu u du u² du a + bu S u du (a + bu)² u du Va + bu du Suva S = = Sufia du u(a + bu) Suca uVa + bu 1 ₂[a + bu a In a + bu] + C b² 1 26³ = = = = du u²(a + bu) du u²(a + bu)² [(a+bu)². 1 a b²a + bu 1 2 362(bu - 2a) Va + bu + C 1 In Forms Involving a + bu In - U 4a(a + bu) + 2a² In a + bul] + C + In a + bu + C Va + bu Va Va + bu + Val + C - a a bu = = - = + = + + C 1 b In {] a U a a bu +221 - -In a + C -1 a + 2bu 26 a² Lu(a + bu) a> 0 ++ bu a C