The polynomial 6x 3 + x 2 + ax 10, where a is a constant, is
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The polynomial 6x3 + x2 + ax − 10, where a is a constant, is denoted by P(x). It is given that when P(x) is divided by (x + 2) the remainder is −12.
a. Find the value of a and hence verify that (2x + 1) is a factor of P(x).
b. When a has this value, solve the equation P(x) = 0.
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a When Px is divided by x 2 the remainder is 12 so we can write Px Qxx 2 12 where Qx is the quotient ...View the full answer
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Related Book For
Cambridge International AS & A Level Mathematics Pure Mathematics 2 & 3 Coursebook
ISBN: 9781108407199
1st Edition
Authors: Sue Pemberton, Julianne Hughes, Julian Gilbey
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