Refer to the previous problem. Conduct the test of Ho A = B by using the fact that if X is Poisson with mean and Y is an independent Poisson variate with mean 2, then X given X + Y is binomial with index n = X + Y and parameter =/( + 2). (Hint: Let X and Y be the total numbers of imperfections for the two treatments; then the test of equal Poisson means reduces to a binomial test of T = when 140 trials have 50 successes.)