a. At (18^{circ} mathrm{C}), the concentration solubility product of (mathrm{AgBr}) is (mathrm{K}_{mathrm{SAgBr}}=4.1 times 10^{-13}(mathrm{~mol} / mathrm{L})^{2}) (Mullin,

Question:

a. At \(18^{\circ} \mathrm{C}\), the concentration solubility product of \(\mathrm{AgBr}\) is \(\mathrm{K}_{\mathrm{SAgBr}}=4.1 \times 10^{-13}(\mathrm{~mol} / \mathrm{L})^{2}\) (Mullin, 2001). What is the concentration of \(\mathrm{AgBr}\) at saturation?

b. If we add \(5.0 \times 10^{-7} \mathrm{~mol} / \mathrm{L}\) of \(\mathrm{NH}_{4} \mathrm{Br}\), what is the final solution concentration of \(\mathrm{AgBr}\) ? What fraction of \(\mathrm{Ag}^{+}\)precipitates?

c. How many moles/L of \(\mathrm{NH}_{4} \mathrm{Br}\) need to be added to a saturated solution of \(\mathrm{AgBr}\) at \(18^{\circ} \mathrm{C}\) to precipitate \(99 \%\) of the silver?

Fantastic news! We've Found the answer you've been seeking!