The ground state of O 2 has two unpaired * electrons with parallel spins. There are two
Question:
The ground state of O2 has two unpaired π* electrons with parallel spins. There are two known low-lying excited states of O2. State A has the two π* electrons with the spins antiparallel but in different orbitals. State B has the two π* electrons paired in the same orbital.
(a) The energies of the excited states are 94.72 kJ · mol–1 and 157.85 kJ · mol–1 above the ground state. Which state corresponds to which excitation energy?
(b) What is the wavelength of the radiation absorbed in the transition from the ground state to the first excited state?
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a State A corresponds to the excitation energy of 9472 kJmol and State B corresponds to 15785 kJmol ...View the full answer
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Related Book For 
Chemical Principles The Quest For Insight
ISBN: 9781464183959
7th Edition
Authors: Peter Atkins, Loretta Jones, Leroy Laverman
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