Question: A ball is thrown straight up into the air. The function y = h(t) in the graph gives the height of the ball (in feet)

A ball is thrown straight up into the air. The function y = h(t) in the graph gives the height of the ball (in feet) at t seconds. The graph does not show the path of the ball. The ball is rising straight up and then falling straight down.

(a) What is the height of the ball at 2 sec?

(b) When will the height be 192 ft?

(c) During what time intervals is the ball going up? down?

(d) How high does the ball go? When does the ball reach its maximum height?

(e) After how many seconds does the ball hit the ground?

Height of a Thrown Ball

पा 256 HJ y = h(t).. %3D 192 128 64 5 6 3 4 Time (in seconds) Height (in feet)

256 HJ y = h(t).. %3D 192 128 64 5 6 3 4 Time (in seconds) Height (in feet)

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a At t 2 y 240 from the graph Therefore at 2 seconds the ball is 240 feet high b At y ... View full answer

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