(a) Calculate the energy released by the fusion of a 1.00-kg mixture of deuterium and tritium, which...

Question:

(a) Calculate the energy released by the fusion of a 1.00-kg mixture of deuterium and tritium, which produces helium. There are equal numbers of deuterium and tritium nuclei in the mixture.

(b) If this takes place continuously over a period of a year, what is the average power output?


Strategy

According to 2H+ 3H-4He+n, the energy per reaction is 17.59 MeV. To find the total energy released, we must find the number of deuterium and tritium atoms in a kilogram. Deuterium has an atomic mass of about 2 and tritium has an atomic mass of about 3, for a total of about 5 g per mole of reactants or about 200 mol in 1.00 kg. To get a more precise figure, we will use the atomic masses from Appendix A. The power output is best expressed in watts, and so the energy output needs to be calculated in joules and then divided by the number of seconds in a year.

Data from Appendix A

Atomic Masses Atomic Number, Z 1 2 3 Name neutron Hydrogen Deuterium Tritium Helium Lithium Atomic Massst 4 5 6 Beryllium Boron Carbon 7 7 9 10 11 11 12 Li 7 Be 9 Be 10B 11B 11C 12C 7.016 003 7.016 928 9.012 182

7 8 9 Nitrogen Oxygen Fluorine 13 14 13. 14 15. 15 16 18 18 13 C 14C 13 N 14N 15 N 150 160 180 18 F 13.003

10 11 Neon Sodium 19 20 22 22 23 24 19 F 20 Ne 22 Ne 22 Na 23 Na 24 Na 18.998 403 19.992 435 21.991 383

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