One long straight wire is to be held directly above another by repulsion between their currents. The
Question:
One long straight wire is to be held directly above another by repulsion between their currents. The lower wire carries 100 A and the wire 7.50 cm above it is 10-gauge (2.588 mm diameter) copper wire.
(a) What current must flow in the upper wire, neglecting the Earth's field?
(b) What is the smallest current if the Earth's 3.00 x 10-5 T field is parallel to the ground and is not neglected?
(c) Is the supported wire in a stable or unstable equilibrium if displaced vertically? If displaced horizontally?
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Step by Step Answer:
a To calculate the current required in the upper wire we can use Amperes law B I 2 r Where B is the magnetic field unknown is the permeability of free ...View the full answer
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