Suppose the following experiment is performed. A 0.250-kg object (m₁) is slid on a frictionless surface into a dark room, where it strikes an initially stationary object with mass of 0.400 kg (m₂) . The 0.250-kg object emerges from the room at an angle of 45.0° with its incoming direction. 

The speed of the 0.250-kg object is originally 2.00 m/s and is 1.50 m/s after the collision. Calculate the magnitude and direction of the velocity (v'₂ and θ₂) of the 0.400-kg object after the collision.

Strategy
Momentum is conserved because the surface is frictionless. The coordinate system shown in Figure 8.11 is one in
which m₂ is originally at rest and the initial velocity is parallel to the -axis, so that conservation of momentum
along the x- and y-axes is applicable.

Transcribed Image Text:

JA Before P1 = Prot mi m₂ = 0.400 kg X V1 net F = 0 V2 = 0 m2 After P' + P₂ = Prot v₂ = ? 0₂ = ? mi ví 0₁ = 45°