Question: Suppose you pass light from a He-Ne laser through two slits separated by 0.0100 mm and find that the third bright line on a screen

Suppose you pass light from a He-Ne laser through two slits separated by 0.0100 mm and find that the third bright line on a screen is formed at an angle of 10.95° relative to the incident beam. What is the wavelength of the light?

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The third bright line is due to third-order constructive interference, which means that m = 3. We are given d = 0.0100 mm and θ = 10.95°. The wavelength can thus be found using the equation d sin θ = mλ for constructive interference.

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