What is the average velocity of the train in part b of Example 2.2, and shown again

Question:

What is the average velocity of the train in part b of Example 2.2, and shown again below, if it takes 5.00 min to make its trip?

Data given in Example 2.2 part b

0 Ax'= -1.50 km 0. x = 3.75 km x = 5.25 km x (km)

Strategy
Average velocity is displacement divided by time. It will be negative here, since the train moves to the left and has a negative displacement.

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