A student opens a uniform 12 -kg door by applying a constant force of \(40 \mathrm{~N}\) at a perpendicular distance of \(0.90 \mathrm{~m}\) from the hinges ( Figure 8.19). If the door is \(2.0 \mathrm{~m}\) in height and \(1.0 \mathrm{~m}\) wide, what is the magnitude of its angular acceleration? (Assume that the door rotates freely on its hinges.)

THINKING IT THROUGH. From the given information, the applied net torque can be calculated. To find the angular acceleration of the door, the moment of inertia is needed. This can be calculated, since the door's mass and dimensions are known.

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EXIT PUSH