A physician is making an image with ultrasound of initial intensity (1000 mathrm{~W} / mathrm{m}^{2}). When the
Question:
A physician is making an image with ultrasound of initial intensity \(1000 \mathrm{~W} / \mathrm{m}^{2}\). When the frequency is set to \(1.0 \mathrm{MHz}\), the intensity drops to \(500 \mathrm{~W} / \mathrm{m}^{2}\) at a certain depth in the patient's body. What will be the intensity at this depth if the physician changes the frequency to \(2.0 \mathrm{MHz}\) ?
A. \(750 \mathrm{~W} / \mathrm{m}^{2}\)
B. \(500 \mathrm{~W} / \mathrm{m}^{2}\)
C. \(250 \mathrm{~W} / \mathrm{m}^{2}\)
D. \(125 \mathrm{~W} / \mathrm{m}^{2}\)
Ultrasound is absorbed in the body; this complicates the use of ultrasound to image tissues. The intensity of a beam of ultrasound decreases by a factor of 2 after traveling a distance of 40 wavelengths. Each additional travel of 40 wavelengths results in a decrease by another factor of 2 .
Step by Step Answer:
College Physics A Strategic Approach
ISBN: 9780321907240
3rd Edition
Authors: Randall D. Knight, Brian Jones, Stuart Field