What is the displacement of the jogger from t = 18.0 min to t = 24.0 min?
Question:
What is the displacement of the jogger from t = 18.0 min to t = 24.0 min?
(a) 720 m, south
(b) 720 m, north
(c) 2160 m, south
(d) 3600 m, north
A jogger is exercising along a long, straight road that runs north-south. She starts out heading north. A graph of vx(t) is shown below.
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The displacement of the jogger from t 180 min to t 240 min is c 216...View the full answer
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Related Book For 
College Physics With An Integrated Approach To Forces And Kinematics
ISBN: 978-1260547719
5th Edition
Authors: Alan Giambattista
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