The following problems deal with translating from MIPS to C. Assume that the variables f, g, h, i, and j are assigned to registers $s0, $s1, $s2, $s3, and $s4, respectively. Assume that the base address of the arrays A and B are in registers $s6 and $s7, respectively.

How many registers are needed to carry out the MIPS assembly as written above? If you could rewrite the code above, what is the minimal number of registers needed?

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25 s11 $s2, $s4, 1 add $50, $s2, $s3 add $50, $s0, $sl b. sll $t0, $s0. 2 add $t0, $56. $t0 s11 $t1, $sl, 2 $t1, $s7, add $t1 Tw $50, 0($t0) addi $t2, $t0, 4 Tw $t0, 0($t2) add $t0, $t0, $t0. 0($th) SW $50 # $to f* 4 &A[f] # sto # $t1 = g * 4 # $t1 = &B[g] # f = = = A[f]