The following problems deal with translating from MIPS to C. Assume that the variables f, g, h, i, and j are assigned to registers $s0, $s1, $s2, $s3, and $s4, respectively. Assume that the base address of the arrays A and B are in registers $s6 and $s7, respectively.

How many registers are needed to carry out the MIPS assembly as written above? If you could rewrite the code above, what is the minimal number of registers needed?

25 s11 $s2, $s4, 1 add $50, $s2, $s3 add $50, $s0, $sl b. sll $t0, $s0. 2 add $t0, $56. $t0 s11 $t1, $sl, 2 $t1, $s7, add $t1 Tw $50, 0($t0) addi $t2, $t0, 4 Tw $t0, 0($t2) add $t0, $t0, $t0. 0($th) SW $50 # $to f* 4 &A[f] # sto # $t1 = g * 4 # $t1 = &B[g] # f = = = A[f]