If the time response of a system is given by the following equation; [ y(t)=5+3 sin left(omega
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If the time response of a system is given by the following equation;
\[
y(t)=5+3 \sin \left(\omega t+\delta_{1}ight)+e^{-3 t} \sin \left(\omega t+\delta_{2}ight)+e^{-5 t}
\]
Then the steady state part of the above response is given by:
(a) \(5+3 \sin \left(\omega t+\delta_{1}ight)\)
(b) \(5+3 \sin \left(\omega t+\delta_{1}ight)+e^{-3 t} \sin \left(\omega t+\delta_{2}ight)\)
(c) \(5+e^{-5 t}\)
(d) 5
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The steady state response of a system is the part of the response that doesnt decay over time ...View the full answer
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