If the time response of a system is given by the following equation;

\[
y(t)=5+3 \sin \left(\omega t+\delta_{1}ight)+e^{-3 t} \sin \left(\omega t+\delta_{2}ight)+e^{-5 t}
\]

Then the steady state part of the above response is given by:
(a) \(5+3 \sin \left(\omega t+\delta_{1}ight)\)
(b) \(5+3 \sin \left(\omega t+\delta_{1}ight)+e^{-3 t} \sin \left(\omega t+\delta_{2}ight)\)
(c) \(5+e^{-5 t}\)
(d) 5