The circle with equation (x 4) 2 + (y + 7) 2 = 50 meets the

Question:

The circle with equation (x − 4)2 + (y + 7)2 = 50 meets the straight line with equation x − y − 5 = 0 at points A and B.

a. Find the coordinates of the points A and B.

b. Find the equation of the perpendicular bisector of line segment AB.

c. Show that the perpendicular bisector of AB passes through the centre of the circle.

d. Find the area of triangle OAB.

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Question Posted: