For a series RL circuit, it can be shown that the rms (I.E., effective value) of the
Question:
For a series R–L circuit, it can be shown that the rms (I.E., effective value) of the asymmetrical fault current is given by the following equation
where θ = f × t is time in cycles X = L/ω = 2π × f × L is the reactance of the inductance Iac is the rms of the ac fault current (also called symmetrical fault current)
A short-circuit occurs in a series R–L circuit with V = 277 V, L = 2 mH, R =0.4. Determine
(a) The rms symmetrical fault current
(b) The rms asymmetrical fault current at the instant the switch closes, assuming maximum DC offset
(c) The rms asymmetrical fault current five cycles after the switch closes, assuming maximum DC offset
(d) The DC offset as a function of time if the switch closes when the instantaneous source voltage is 300 V
Step by Step Answer:
Energy Efficient Electrical Systems For Buildings
ISBN: 9781482258332
1st Edition
Authors: Moncef Krarti