Question: [09] Show that with basis B = {0, 1}, we have M() < 1 and M(x) > M(x0) + M(x1), for all x in B

[09] Show that with basis B = {0, 1}, we have M() < 1 and M(x) > M(x0) + M(x1), for all x in B∗ (strict inequality). Generalize this to arbitrary B.

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