Question: 17. The sequence (Xi ) of independent, identically distributed random variables is such that P(Xi = 0) = 1 p, P(Xi = 1) =
17. The sequence (Xi ) of independent, identically distributed random variables is such that P(Xi = 0) = 1 − p, P(Xi = 1) = p.
If f is a continuous function on [0, 1], prove that Bn(p) = E
f
X1 + · · · + Xn n
152 The main limit theorems is a polynomial in p of degree at most n. Use Chebyshev’s inequality to prove that for all p with 0 ≤ p ≤ 1, and any ǫ > 0, X k∈K
n k
pk (1 − p)n−k ≤
1 4nǫ2
, where K = {k : 0 ≤ k ≤ n, |k/n − p| > ǫ}. Using this and the fact that f is bounded and uniformly continuous in [0, 1], prove the following version of the Weierstrass approximation theorem:
lim n→∞
sup 0≤p≤1 | f (p) − Bn(p)| = 0.
(Oxford 1976F)
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