Question: since the integrand in the latter integral is the density function of the normal distribution with mean t and variance 1, and thus has integral
since the integrand in the latter integral is the density function of the normal distribution with mean t and variance 1, and thus has integral 1. The moment generating function MX (t) exists for all t ∈ R. △
Example 7.45 If X has the exponential distribution with parameter λ, then MX (t) =
Z
∞
0 et xλe−λx dx =
λ
λ − t if t < λ,
∞ if t ≥ λ,
(7.46)
so that MX (t) exists only for values of t satisfying t < λ. △
Example 7.47 If X has the Cauchy distribution, then MX (t) =
Z
∞
−∞
et x 1
π(1 + x2)
dx =
(
1 if t = 0,
∞ if t 6= 0, so that MX (t) exists only at t = 0.
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