Fill in the blanks. Show your work. a. 1090 J = ________ Cal. b. _______ ft
Question:
Fill in the blanks. Show your work.
a. 1090 J = ________ Cal.
b. _______ ft ∙ lbf = energy to lift a 13 N weight through an elevation difference of 115 m.
c. 17000 Btu = ________ kWh.
d. 71 ft ∙ lbf/s = ________ hp.
e. [E] = [energy] = ________
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a 1090 J 25952 Cal To convert Joules to Calories we use the conversion factor of 1 Cal 4184 J 1090 J ...View the full answer
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Related Book For
Engineering Fluid Mechanics
ISBN: 9781118880685
11th Edition
Authors: Donald F. Elger, Barbara A. LeBret, Clayton T. Crowe, John A. Robertson
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