Question: The 20 ft wide rectangular channel shown has three different reaches. S 0 , 1 = 0.01; S 0 , 2 = 0.0004; S 0

The 20 ft wide rectangular channel shown has three different reaches. S0,1 = 0.01; S0,2 = 0.0004; S0,  = 0.00317; Q = 500 cfs; n1 = 0.015; normal depth for reach 2 is 5.4 ft and that for reach 3 is 2.7 ft. Determine the critical depth and normal depth for reach 1 (use Manning’s equation from §15.3). Then classify the flow in each reach (supercritical, subcritical, critical), and determine whether a hydraulic jump could occur. In which reach(es) might it occur if it does occur?Elevation = 1274 ft - Elevation = 1272 ft Elevation = 1270

Elevation = 1274 ft - Elevation = 1272 ft Elevation = 1270 ft Elevation = 1265 ft Elevation = 1264.4 ft e Elevation = 1261.2 ft Reach 1 Reach 2 Reach 3

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To determine the critical depth and normal depth for reach 1 we can use Mannings equation Q 1n A R23 S12 where Q is the flow rate n is Mannings roughn... View full answer

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