Based on your measurements so far, if the mechanical efficiency of the lawnmower engine is 0.50, what
Question:
Based on your measurements so far, if the mechanical efficiency of the lawnmower engine is 0.50, what is the power output of the lawnmower engine, in kW, when it is operating at 2.50 x 103 RPM with a mass air-to fuel ratio of 15 (kg air)/(kg fuel) with a fuel that gives 45,500 kJ/kg of energy?
Refer to a 3.5 horsepower lawn mower engine at a nominal speed of 2.50 × 103 RPM. A typical lawn mower engine, and the inside of its cylinder head, is shown below. Note: the depression in the cylinder head is the clearance for the engine’s valves. If such an engine is available to you in class, you can disassemble it and measure the bore, stroke, and clearance volume, CV, of the engine.
Step by Step Answer:
Exploring Engineering An Introduction to Engineering and Design
ISBN: 978-0123747235
2nd edition
Authors: Philip Kosky, George Wise, Robert Balmer, William Keat