Question: Figure 3.6.2 shows an acute triangle with angles A, B, and C and opposite sides a, b, and c. By dropping a perpendicular from each

Figure 3.6.2 shows an acute triangle with angles A, B, and C and opposite sides a, b, and c. By dropping a perpendicular from each vertex to the opposite side, derive the equations


c cos B + bcos C = a c cos A +


Regarding these as linear equations in the unknowns cosA, cosB, and cosC, use Cramer’s rule to derive the law of cosines by solving for


a cos C = b a cos B + bcos A =


Thus


a2 = b2 + c2 - 2bc cosA.


Note that the case A = π/2 (90°) reduces to the Pythagorean theorem.


c.

c cos B + bcos C = a c cos A + a cos C = b a cos B + bcos A = c.

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