Let g(t) = u(t - /k) f (t - /k), where f(t) is the function of Problem 29 and k > 0. Note that h(t)

Let g(t) = u(t - π/k) f (t - π/k), where f(t) is the function of Problem 29 and k > 0. Note that h(t) = f(t) + g(t) is the full-wave rectification of sin kt shown in Fig. 10.5.16. Hence deduce from Problem 29 that.

Problem 29

Suppose that f (t) is the half-wave rectification of sin kt , shown in Fig. 10.5.15. Show that

L{h(t)} = k s2+k TS 2k coth-